3 uždavinys

Sprendimas: $$\frac{x}{x-3}-\frac{x-1}{x+3} = \frac{x\cdot x+3-x-1\cdot x-3}{(x-3)\cdot (x+3)} = \frac{(x^{2}+x\cdot 3)-(x^{2}-3\cdot x-x+3)}{x^{2}-9} = \frac{x^{2}+x\cdot 3-x^{2}+3\cdot x+x-3}{x^{2}-9} = \frac{7\cdot x-3}{x^{2}-9}$$

Atsakymas: C