12 uždavinys
Sprendimas.
e^(b-2)-2 =
0
0
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e^(b-2)-2 = 0$$e^{(b-2)}-2$$ = $$0$$
e^(b-2) = 0+2$$e^{(b-2)}$$ = $$0+2$$
e^(b-2) = 2$$e^{(b-2)}$$ = $$2$$
ln( e^(b-2)) = ln(2)$$ln(e^{(b-2)})$$ = $$ln(2)$$
$${\normalsize ln(e^{(b-2)})}$$ = $${\normalsize (b-2)}$$
(b-2) = ln(2)$$(b-2)$$ = $$ln(2)$$
$$e^{(b-2)}-2$$ = $$0$$
$$e^{(b-2)}$$ = $$2$$
$$ln(e^{(b-2)})$$ = $$ln(2)$$
$$(b-2)$$ = $$ln(2)$$
$$b = 2+ln(2)$$
Atsakymas: C